![]() From car rentals to limousines, there’s an option for every budget. Ford International Airport ( IATA: GRR, ICAO: KGRR, FAA LID: GRR) is a commercial airport in Cascade Township approximately 13 …GFIA has a variety of options for ground transportation upon your arrival. If the weight of the bag of sugar is 1.4 lb and the weight of each piece of butter is 3.8 – 1.4 = 2.4, so the weight of each piece of butter is 2.4 ÷ 6 = 0.4 lb.Sources GRR and FAA Gerald R. If the weight of the bag of sugar is 1.4 lb, what is the weight of each piece of butter?Īnswer:- The total weight of 6 pieces of butter and a bag of sugar is 3.8 lb. The total weight of 6 pieces of butter and a bag of sugar is 3.8 lb. The cost of each kg Shrimp is $40.68 ÷ 3 = $13.56 What’s the cost of 1 kilogram of shrimp?Īnswer:- Mrs. She saves $0.12Įureka Math Grade 5 Module 1 Lesson 14 Exit Ticket Answer KeyĪnswer:- 0.576 ÷ 4 = 0.144 Eureka Math Grade 5 Module 1 Lesson 14 Homework Answer Key ![]() How much money did she save per avocado? Use a tape diagram, and show your calculations.Īnswer:- 0.94 – 0.82 = 0.12. During a sale, she gets 5 avocados for $4.10. Nguyen used 1.48 meters of netting to make 4 identical mini hockey goals and per each goal she used 0.37m of nettingĮsperanza usually buys avocados for $0.94 apiece. ![]() How much netting did she use per goal?Īnswer:- Mrs. ![]() Nguyen used 1.48 meters of netting to make 4 identical mini hockey goals. When divided any number with any number its quotient will be less than the dividend number so 1.47 is dividing into 7 parts and the answer will be 0.21 which is incorrect because 1.47 ÷ 7 which is not equal to 2.1 and 2.1 is greater than 1.47 Use words, numbers, or pictures to explain why Grayson’s thinking is incorrect.Īnswer:- Grayson wrote 1.47 ÷ 7 = 2.1 in her math journal. ![]() Grayson wrote 1.47 ÷ 7 = 2.1 in her math journal. Show each step using the standard algorithm. Engage NY Eureka Math 5th Grade Module 1 Lesson 14 Answer Key Eureka Math Grade 5 Module 1 Lesson 14 Problem Set Answer Keyĭraw place value disks on the place value chart to solve. ![]()
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